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# -*- coding: utf-8 -*-
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# Copyright (c) 2018-2022 tecnovert
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# Distributed under the MIT software license, see the accompanying
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# file LICENSE or http://www.opensource.org/licenses/mit-license.php.
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import json
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import time
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import decimal
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COIN = 100000000
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decimal_ctx = decimal.Context()
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decimal_ctx.prec = 20
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class TemporaryError(ValueError):
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pass
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class AutomationConstraint(ValueError):
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pass
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def ensure(v, err_string):
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if not v:
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raise ValueError(err_string)
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def toBool(s) -> bool:
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return s.lower() in ['1', 'true']
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def jsonDecimal(obj):
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if isinstance(obj, decimal.Decimal):
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return str(obj)
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raise TypeError
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def dumpj(jin, indent=4):
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return json.dumps(jin, indent=indent, default=jsonDecimal)
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def dumpje(jin):
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return json.dumps(jin, default=jsonDecimal).replace('"', '\\"')
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def SerialiseNum(n):
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if n == 0:
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return bytes((0x00,))
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if n > 0 and n <= 16:
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return bytes((0x50 + n,))
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rv = bytearray()
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neg = n < 0
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absvalue = -n if neg else n
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while(absvalue):
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rv.append(absvalue & 0xff)
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absvalue >>= 8
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if rv[-1] & 0x80:
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rv.append(0x80 if neg else 0)
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elif neg:
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rv[-1] |= 0x80
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return bytes((len(rv),)) + rv
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def DeserialiseNum(b, o=0) -> int:
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if b[o] == 0:
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return 0
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if b[o] > 0x50 and b[o] <= 0x50 + 16:
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return b[o] - 0x50
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v = 0
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nb = b[o]
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o += 1
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for i in range(0, nb):
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v |= b[o + i] << (8 * i)
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# If the input vector's most significant byte is 0x80, remove it from the result's msb and return a negative.
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if b[o + nb - 1] & 0x80:
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return -(v & ~(0x80 << (8 * (nb - 1))))
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return v
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def float_to_str(f):
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# stackoverflow.com/questions/38847690
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d1 = decimal_ctx.create_decimal(repr(f))
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return format(d1, 'f')
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def make_int(v, scale=8, r=0): # r = 0, no rounding, fail, r > 0 round up, r < 0 floor
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if type(v) == float:
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v = float_to_str(v)
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elif type(v) == int:
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return v * 10 ** scale
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sign = 1
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if v[0] == '-':
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v = v[1:]
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sign = -1
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ep = 10 ** scale
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have_dp = False
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rv = 0
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for c in v:
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if c == '.':
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rv *= ep
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have_dp = True
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continue
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if not c.isdigit():
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raise ValueError('Invalid char: ' + c)
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if have_dp:
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ep //= 10
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if ep <= 0:
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if r == 0:
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raise ValueError('Mantissa too long')
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if r > 0:
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# Round up
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if int(c) > 4:
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rv += 1
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break
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rv += ep * int(c)
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else:
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rv = rv * 10 + int(c)
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if not have_dp:
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rv *= ep
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return rv * sign
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def validate_amount(amount, scale=8) -> bool:
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str_amount = float_to_str(amount) if type(amount) == float else str(amount)
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has_decimal = False
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for c in str_amount:
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if c == '.' and not has_decimal:
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has_decimal = True
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continue
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if not c.isdigit():
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raise ValueError('Invalid amount')
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ar = str_amount.split('.')
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if len(ar) > 1 and len(ar[1]) > scale:
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raise ValueError('Too many decimal places in amount {}'.format(str_amount))
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return True
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def format_amount(i, display_scale, scale=None):
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if not isinstance(i, int):
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raise ValueError('Amount must be an integer.') # Raise error instead of converting as amounts should always be integers
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if scale is None:
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scale = display_scale
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ep = 10 ** scale
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n = abs(i)
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quotient = n // ep
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remainder = n % ep
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if display_scale != scale:
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remainder %= (10 ** display_scale)
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rv = '{}.{:0>{scale}}'.format(quotient, remainder, scale=display_scale)
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if i < 0:
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rv = '-' + rv
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return rv
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def format_timestamp(value, with_seconds=False):
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str_format = '%Y-%m-%d %H:%M'
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if with_seconds:
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str_format += ':%S'
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str_format += ' %Z'
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return time.strftime(str_format, time.localtime(value))
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def b2i(b) -> int:
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# bytes32ToInt
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return int.from_bytes(b, byteorder='big')
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def i2b(i: int) -> bytes:
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# intToBytes32
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return i.to_bytes(32, byteorder='big')
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def b2h(b: bytes) -> str:
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return b.hex()
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def h2b(h: str) -> bytes:
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if h.startswith('0x'):
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h = h[2:]
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return bytes.fromhex(h)
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def i2h(x):
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return b2h(i2b(x))
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